8+x-[x(x-1)]=0

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Solution for 8+x-[x(x-1)]=0 equation:


Simplifying
8 + x + -1[x(x + -1)] = 0

Reorder the terms:
8 + x + -1[x(-1 + x)] = 0
8 + x + -1[(-1 * x + x * x)] = 0
8 + x + -1[(-1x + x2)] = 0
8 + x + [-1x * -1 + x2 * -1] = 0
8 + x + [1x + -1x2] = 0

Combine like terms: x + 1x = 2x
8 + 2x + -1x2 = 0

Solving
8 + 2x + -1x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(4 + -1x)(2 + x) = 0

Subproblem 1

Set the factor '(4 + -1x)' equal to zero and attempt to solve: Simplifying 4 + -1x = 0 Solving 4 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1x = 0 + -4 -1x = 0 + -4 Combine like terms: 0 + -4 = -4 -1x = -4 Divide each side by '-1'. x = 4 Simplifying x = 4

Subproblem 2

Set the factor '(2 + x)' equal to zero and attempt to solve: Simplifying 2 + x = 0 Solving 2 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Solution

x = {4, -2}

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